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Title | Use the FormatNumber function in Visual Basic .NET |
Description | This example shows how to use the FormatNumber function in Visual Basic .NET. |
Keywords | FormatNumber, format number, VB.NET |
Categories | Strings, VB.NET |
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The FormatNumber function returns a formatted string representation for a number. The syntax is:
FormatNumber(expression _
[, digits_after_decimal] _
[, include_leading_zero] _
[, use_parens_if_negative] _
[, groups_digits] )
Where:
- expression
- The numeric expression to format
- digits_after_decimal
- The number of digits to display after the decimal point
- include_leading_zero
- If the number is less than 1 and greater than -1, determines whether the number should have a leading 0 before the decimal point.
- use_parens_if_negative
- Determines whether negative numbers are surrounded with parentheses instead of using a minus sign.
- groups_digits
- Determines whether digits to the left of the decimal point are grouped with thousands separators (commas in the United States).
Examples:
Expression | Result |
FormatNumber(1.23456, 2) | 1.23 |
FormatNumber(0.123456, 2, TriState.False) | .12 |
FormatNumber(0.123456, 2, TriState.True) | 0.12 |
FormatNumber(-12345.12, , TriState.False) | -12,345.12 |
FormatNumber(-12345.12, , TriState.True) | (12,345.12) |
FormatNumber(-12345.12, , TriState.True, TriState.False) | (12345.12) |
This example uses the following code to display these examples in a TextBox.
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Private Sub Form1_Load(ByVal sender As System.Object, ByVal _
e As System.EventArgs) Handles MyBase.Load
Dim txt As String
Dim x As Single
x = 1.23456
txt &= "FormatNumber(" & x.ToString() & ", 2) = " & _
FormatNumber(x, 2) & vbCrLf
x = 0.123456
txt &= "FormatNumber(" & x.ToString() & ", 2, " & _
"TriState.False) = " & FormatNumber(x, 2, _
TriState.False) & vbCrLf
txt &= "FormatNumber(" & x.ToString() & ", 2, " & _
"TriState.True) = " & FormatNumber(x, 2, _
TriState.True) & vbCrLf
x = -12345.12345
txt &= "FormatNumber(" & x.ToString() & ", , " & _
"TriState.False) = " & FormatNumber(x, 2, , _
TriState.False) & vbCrLf
txt &= "FormatNumber(" & x.ToString() & ", , " & _
"TriState.True) = " & FormatNumber(x, 2, , _
TriState.True) & vbCrLf
txt &= "FormatNumber(" & x.ToString() & ", , " & _
"TriState.True, TriState.False) = " & _
FormatNumber(x, 2, , TriState.True, TriState.False) _
& vbCrLf
txtResult.Text = txt
txtResult.Select(0, 0)
End Sub
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